Q] 4 male prisoners were occasionally given chocolate for their hardships in jail. On one day, 11 chocolates were given out to the prisoners, however, the prisoners don’t know how many chocolates each of them had. So they decided to start a conversation: Prisoner 1: “Prisoner 2, did you have more chocolates than me?” Prisoner 2: “I don’t know. Hey, Prisoner 3, did you have more chocolates than me?” Prisoner 3: “I don’t know.” Hearing the conversation, Prisoner 4 replies to everyone. Prisoner 4: “I know exactly how many chocolates each of you had.”
How many chocolates did each prisoner have?
Answer: If you worked your way through this riddle, then you would have found yourself with the following answers: Prisoner 1: 1 chocolate Prisoner 2: 2 chocolates Prisoner 3: 3 chocolates Prisoner 4: 5 chocolates Logic would have got you through this one. Prisoner 4 must have eaten 5 or more chocolates since he did not ask the question, “Did you have more chocolates than me?”. Prisoner 1 can’t have eaten 5 or more chocolates so prisoner 1 must have eaten 1-4 chocolates. Prisoner 2 must have eaten 2-4 chocolates since prisoner 1 asked him whether he had more chocolates than him meaning prisoner 2 knew that prisoner 1 ate 1-4 chocolates otherwise he would have said “No” if he had 1 chocolate. Prisoner 3 answered, “I don’t know” when asked whether he had more chocolates by prisoner 2, so he would have known that prisoner 2 must have eaten at least 2 chocolates. Going by the same logic prisoner 2 went with, prisoner 3 must have known that prisoner 2 would have had at least 2 chocolates meaning he would have had 3 or 4 chocolates himself otherwise he would have answered “No” if he had 2 chocolates. Lastly, prisoner 4 must have eaten 5 chocolates which would add up to 11 chocolates between the 4 prisoners as he knew how many chocolates each of the other prisoners had. Therefore, leaving prisoner 1 with one chocolate, prisoner 2 with two chocolates, prisoner 3 with three chocolates and prisoner 4 with five chocolates.
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